math-lab

voting · paradox

Ostrogorski's paradox

Party X and Party Y disagree about a school, about taxes, and about roads. Each person votes for the party they agreed with more often.

Party X and Party Y are the two parties running against each other. They disagree about a new school, about raising taxes, and about fixing the roads. On each thing, each person says which party they agree with. The election is a separate vote: each person votes for the party they agreed with on more of those three things.

Voter 1 agrees with Party Y on the school and on taxes, and with Party X on the roads. That is two things for Party Y and one for Party X. The rule says voter 1 votes for Party Y.

Voters 2 and 3 also agree with Party Y on two things, so they vote for Party Y too. They are yellow. Voters 4 and 5 agree with Party X on all three things, so they vote for Party X. They are green.

On the school, 3 people agree with Party X and 2 agree with Party Y. Taxes is the same, 3 to 2. The roads are the same, 3 to 2.

The election is 3 votes for Party Y and 2 for Party X. Party Y wins.